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-21=5.4t-4.9t^2
We move all terms to the left:
-21-(5.4t-4.9t^2)=0
We get rid of parentheses
4.9t^2-5.4t-21=0
a = 4.9; b = -5.4; c = -21;
Δ = b2-4ac
Δ = -5.42-4·4.9·(-21)
Δ = 440.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5.4)-\sqrt{440.76}}{2*4.9}=\frac{5.4-\sqrt{440.76}}{9.8} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5.4)+\sqrt{440.76}}{2*4.9}=\frac{5.4+\sqrt{440.76}}{9.8} $
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